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5-2x-x-x^2=0
We add all the numbers together, and all the variables
-1x^2-3x+5=0
a = -1; b = -3; c = +5;
Δ = b2-4ac
Δ = -32-4·(-1)·5
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{29}}{2*-1}=\frac{3-\sqrt{29}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{29}}{2*-1}=\frac{3+\sqrt{29}}{-2} $
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